Further Mathematics Paper 2, Nov/Dec. 2010
 Questions: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 Main
Weakness/Remedies
Strength
Question 6

The table gives the distribution of heights, in metres, of 100 students of the same age group.

(a) Calculate the mean height of the distribution.
(b) What is the probability that the height of a student selected at random is greater than the mean height of the distribution?

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Observation

This question was reported to be well attempted by majority the candidates who were said to have demonstrated a good knowledge of the topic. Majority of the candidates were able to obtain the class mark for each interval, calculate the mean height and find the required probability.

 Heicht Class Mark (x) Freauencv (f) fx 1.40 -1-42 1.41 2 2.82 1.43 -1.45 1.44 4 5.76 1.46 - 1.48 1.47 19 27.93 1.49-1.51 1.50 30 45.00 1.52 -1.54 1.53 24 36.72 1.55 -1.57 1.56 14 21.84 1.58 -1.60 1.59 6 9.54 1.61 -1.63 1.62 1 1.62 >. f = 100 L Ix = 151.23

Mean = ∑fx/∑f = 151.23 = 1.5123
100
Probability (height> mean height) = 45/100 = 0.45 or 9/20