In part (a), it was reported that the indicial equation was attempted correctly. However, some candidates did not express 8 as 23 and 1 as 30 and so were not able to solve the equations. Candidates were expected to write 8 = 2(x + y) as 23 = 2(x + y) and equate the powers to obtain 3 = x + y. Similarly, they were to obtain the second equation as 30 = 3(x – y) i.e. 0 = x – y. Solving these equations simultaneously gave the solution x = y = 1 .

In part (b), candidates’ expected response was as follows:

Multiplying the given expression by the LCM of the denominators gave 4(3x + 2y)

= 9(5x – 4y) which after simplifying we obtain 3x = 4y. Hence, = . Majority of the candidates also attempted this question correctly however; some candidates were reported to have started off well but were not able to get the final answer by dividing appropriately.