Majority of the candidates found this question rather challenging because they could not manipulate the concept of similar figures to find h, the height of the removed cone i.e.
h = 16 + h
6 10 which gives h = 24cm.
Very few of them were able to apply the formular for finding the volume of a frustum V = 1/3 π/ h (R2 + Rr + r2), where V = volume of a frustum.
