waecE-LEARNING
Physics Paper 2, MAy/June. 2013  
Questions: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 Main


General Comments
Weakness/Remedies
Strength

























Question 5

A mass of 11.0 kg is suspended from a rigid support by an aluminium wire of length 2.0m, diameter 2.0 mm and Young’s modulus 7.0 x 1011 Nm-2.  Determine the extension produced.  [ g = 10ms-2;  = 3.142]
This question was well attempted by most candidates however, some could not handle the arithmetic successfully.  Evaluation of the cross-sectional area where some conversion such as mm to m, mm2 to m2 are necessary posed difficulty for some candidates.


_____________________________________________________________________________________________________
Observation

 

The expected answer is:
E  =   
        OR
e    =                                                                                                       

110 x 2.0
    7.0 x 1011x3.142 x ()2
                                4                                                                                  
            = 1.0 X 10-4 m   OR   0.10 mm               

                  

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