This question was also reported to be attempted by majority of the candidates and they performed well in it.
In part (a) candidates were reported to have expanded the right hand side to have 5
2-10
+5
2 i.e 
2 – 
2 = 5
2 – 10
+ 5
2. Bringing like terms together gave 4y2 – 10xy + 6x2 = 0. Factorizing gave 4y2 – 4
– 6
+ 6
2 = 0 i.e (4y-6
)(y-
) = 0 which implied that either y = x or 4y = 6
. Hence, the ratio x:y = 1:1 or 2:3.
In part(b), candidates were reported to have shown that if 
of the total profit was N84,000.00, then the total profit = 
= N210,000.00. Ajayi’s share would then be gotten as 
of 210,000 = N126,000.00. Let Kunle’s contribution to the partnership be x, then Ajayi’s contribution = 
+ 500,000. From the second statement, 
x 
= 210,000. Solving this equation gave 
= N450, 000.00. This meant that Kunle contributed N450, 000.00 to the partnership.
of the total profit which amounted to N84,000.00, how much was: