waecE-LEARNING
Physics Paper 2, May/June. 2010  
Questions: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 Main
General Comments
Weakness/Remedies
Strength











Question 1

A stone is projected vertically upward with a speed of 30 ms" from the top of a tower of
height 50 m. Neglecting air resistance, determine the maximum height it reached from
the ground
[g = 10 ms2]

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Observation

Generally, candidates reacted to the given numerical satisfactorily. However, some
candidates failed to go further to determine the height from the ground as demanded by
the question by adding 50m.
The expected answer is:
v2 =u2 - 2gx
At maximum height v = 0
o = 302 - 2 x lOx
o = 900 - 20 x
x = 45m.
Height from ground = 50 + 45
= 95m

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