This question was quite unpopular with the candidates. The expected responses were as follow:
Let m ~ [;]. Then RQ ~ MP Le. [~] - [-;] ~ [~5J - [;]
which gives [; ] ~ (=~] which implies that the position vector of m is -2i - 6j.
For the (~art,;;;;" [:::~) - ~5)" [ :::~) thus JPW " v36 + 1 "
Similarly PQ =[ ~] - (-~ = l~J
/PQj = ";9 + 64 = ";73.
Let e be the angle between them,
then [=~. (-~] ~[m J [~ Cos e which gives e = 78.9°.
Area of PQRM =
M Sin e = 51sq.units
