This question was reportedly attempted by majority of the candidates and they performed well in it, they were able to express + . Multiplying both sides by the LCM and comparing coefficients gave P = 3, R = 0 and Q = 1. Thus the partial fractions are: = + .
In part (b), since y = (x + 1, = 1/2(x + 1 . But i.e. = 2(x + 1) = 1. Hence x = -1/2
in partial fractions.
, determine the value of x for which 
= y. 
+ 
. Multiplying both sides by the LCM and comparing coefficients gave P = 3, R = 0 and Q = 1. Thus the partial fractions are: 
= 
+ 
.
, 
= 1/2(x + 1
. But 
i.e. 
= 
2(x + 1) = 1. Hence x = -1/2