The performance of most of the candidates who attempted this question were found to be satisfactory. They were able to determine the mode which was 2.  They obtained the number of at least 2 children to be 16.  Therefore the probability of at least 2 children = =  . The number of families with one child = 5 hence the required sectoral angle =  x 360° = 75°.
 However, a good number of the candidates while calculating the 3rd quartile obtained the position of the third quartile i.e. 3rd quartile = ¾ x 24 = 18th position but failed to obtain the third quartile which was 3.