The part (a) of this question was reported to be well attempted and candidates’ performance was said to be commendable. They were able to obtain the equation 15 + y –y + 17 –y + 4 = 30 which gave y = 6.

It was also reported that candidates’ general performance in part (b) was not as high as it was in part (a). Majority of the candidates could not draw the diagram correctly. Some candidates mistook corresponding angles for alternate angles. They were expected to draw the diagrams as shown

From the diagram, <MNP = <NRQ = 75° (corresponding angles as MN is parallel to QR). Therefore <MNQ = 125° – 75° = 50°.  <NQR = <MNQ = 50° (alternate angles, MN//QR).  <NPM = (180° – 125°)/2 (base angles of isosceles triangle PNQ) which gives <NPQ = 27.5°.