This question was reported to be very popular among the candidates. Majority of them attempted it and they performed very well in it.
In part(a), candidates were reported to have multiplied both sides of the equality sign by the LCM of 2 and to have 2 – 3 + 2 = 0. Solving this quadratic equation gave = 1 and 2.

In part (b), candidates were reportedly able to show that since the range was 16, then q - p = 16. Similarly, since the mean was 9, it implied that p+6+8+11+q = 9 x 5 = 45. Hence, p + q = 20. Solving the two equations simultaneously gave p = 2 and q = 18. Therefore (2p + q) = 2(2) + 18 = 22.