Question 10

In this question, many candidates were reported not to have heeded the given instruction.  Candidates were expected to sketch the two curves but many of them obtained tables of values and drew the curve.  Each of the curves could be sketched by determining the points of intersection of each curve with the x and y axis as well as the turning points as shown in the diagram.

The points of intersection were obtained, by solving the equation y₁ = y₂ i.e.  6 – x - x² = 3x² - 2x + 3 as x = 1 or x = -3/4.  The enclosed area =  = .