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General Mathematics Paper 2,May/June. 2009  
Questions: 1 2 3 4 5 6 7 8 9 10 11 12 13 Main
General Comments
Weakness/Remedies
Strength








Question 11
(a) A circle is inscribed in a square.  If the sum of the perimeter of the square and the circumference of the circle is 100 cm, calculate the radius of the circle.   [Take p = ]

(b)   A rope 60cm long is made to form a rectangle.  If the length is 4 times its breadth, calculate, correct to one decimal place, the

(i) length;

(ii) diagonal

of the rectangle.

 

_____________________________________________________________________________________________________
Observation
 

In part (a), majority of the candidates could not translate the question into a meaningful diagram.  Others who were able to draw it took the length of the square to be r instead of 2r hence they lost some marks.  Perimeter of the square = 8r, circumference of the circle = 2pr. Thus     2pr + 8r = 100 i.e.  + 8r = 100 Þ r = 7cm.

It was reported that majority of the candidates did not attempt the part (b).  Some of them who attempted it could not manipulate the algebraic expressions involved.  Since the length was said to be four times the breadth, it means that if the breadth    = b, then length (L) = 4b. The perimeter was given as 60cm.Therefore, perimeter= 2(L + b) = 2 (4b+b) = 10b = 60. Solving this gave b = 6cm. Hence, length (L) = 6 x 4 = 24cm.  Diagonal = √242+62) = 24.7cm.

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