Candidates' performance in part (a) was reported to be poor. A good number of them were reported not to have attempted this part of the question. They were expected to recall that lkm = 100,000 ern, therefore 1km2 = 1km x 1km = 100,000 x 100,000 = 10,000 000,OOOcm²•
85km² = 850,000,000,000 em". 20,000 em on the ground = 1 cm on the map, hence 400,000,000 em² on the ground = 1 cm²2 on the ground is equivalent to 850,000,000,000 = 2125 cm² on the map.                                                                                                                                        400,000,000
In part (b), candidates' performance was said to be better than it was in part (a). However, many candidates did not draw the diagram correctly and so were not able to solve the problem.

 

From the diagram, area of path = 2(30 x 6) + 12a = 360 + 12a. Area of field = 18a. Since they are equal, 18a = 12a + 360. This gave a = 60 m.

In part (c), candidates' performance was described as fair. However, some candidates did not see the reflex angle as 360 - x, hence, did not subtract their final answer from 360° when they had calculated the value of the reflex angle. Here, 360 - x x 22x Z x Z = 27.5 cm2
                                      360        7       2 2

This meant that 360 - x = 360 x 2 x 27.5 from where we obtain x = 103° to the nearest degree
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