The expected answers were:
(a) (i)
(ii)
(iii)
w = 2rcf = 100 tt
f= ~=50 Hz
211:
Average value = 2xpeakvalue= 0.636 x peak value
11:
= 2xlOV = 0.636 x 10 = 6.36 V
11:
1
rms value = .,f2Vpeak
= 0.707 x Vpeak = 7.07 V
(b) v ~
Peak-to-peak
value
~----~r------'I--+t
Period I
t+--";"';;;';'~I-----w:
I
I
I
----:v;-----------------
The question was on Circuit Analysis. The question was very unpopular with the
candidates. The performance was reported fair.
