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Further Mathematics Paper 2, May/June. 2009  
Questions: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 Main
General Comments
Weakness/Remedies
Strength

Question 2

Solve the simultaneous equations
           log2x – log2y   = 2,
           log2 (x- 2y)   = 3.

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Observation

Candidates were expected to derive the two equations by applying the appropriate theory of logarithms. log2x –log2y = 2 ≡ log2 x/y = 2 which implies that x/y = 22 = 4 or x = 4y.  Similarly, log2 (x - 2y) = 3 implies that x -2y = 8.  Solving these two equations simultaneously resulted in
 x = 16 and y = 4.

This question was reported to have been attempted by majority of the candidates and they performed well in it.

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