The Chief Examiner described the performance of candidates in this question as fair.  Majority of them could not apply the quotient rule of differentiation correctly.  Candidates were expected to show that if y =  = , then  = . Here, v = x + 1 and u = 1.  = 1 and  = 0. Hence,  =  =  = . At x= 1,  =  =   and y =
Therefore, the required equation of the tangent was y -  = (x – 1) which simplified to x + 4y – 3 = 0.