The Chief Examiner reported that this was also a very popular question among the candidates and they performed well in it. Majority of the candidates were reported to have recalled that for a given set of numbers, the sum of all the deviations from the mean = 0. i.e. -2 + x+7 (x+2)2 + (x+3)2 = 0. Expanding the squares and simplifying the equation gave x2 + 6x + 9 = 0 i.e. (x+3)2 = 0 Hence, x = -3.