waecE-LEARNING
Further Mathematics Paper 2, Nov/Dec. 2014  
Questions: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 Main
General Comments
Weakness/Remedies
Strength








Question 5

Events A and B are such that P(A) =  and  P(B) = .
Find P(A È B) if events A and B are:

(a)  mutually exclusive;

(b)  independent.

 

 

 

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Observation

This question was reported to be quite popular among the candidates and they performed well in it. Majority of the candidates were reported to correctly recall the relation P(AÈB) = P(A) + P(B) – P(AÇB). However, it was also observed that in part (a) some candidates multiplied the respective probabilities instead of adding them. 
In part (a), since the events were mutually exclusive, P(A Ç B) = 0.  Therefore, P(A È B) = P(A) + P(B) =  +  = .
In part (b), since the events were independent, then P(A Ç B) = P(A) × P(B) =  ×   = . Therefore, P = P(A) + P(B) – P(A  - .

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