Question 2
QUESTION 2
(a) Consider the following reaction  equation:
        MnO4-  +  C2O42-  +   H+   Mn2+ + CO2 +  H2O
         (i)         State  the condition under which the reaction occurs.
         (ii)        List  the species that is:
                        I. oxidized;
                        II. reduced.
         (iii) Write a  balanced equation for the reduction half reaction. [5  marks]
(b) (i)   List five steps in the treatment of water  for town supply.
        (ii)  Describe briefly each of the steps listed in  2 (b)(i).  [10  marks]
      
(c) Consider the following elements: 12Q, 17R, 20S
(i) Write the electron configuration of  each of the elements:
  12Q;
17R;
20S.
(ii) Explain briefly why Q shows similar chemical properties as S but different chemical properties from R.
(iii) Write the formula of the compound formed  when R combine with S. [7  marks]
        
        (d)Calculate the number of moles of hydrogen ions in 1 dm3 of a 0.1 mol dm-3  tetraoxosulphate (VI) acid solution. [3  marks]
Observation
This question was popular among the candidates. Majority of them attempted it, and their performance was above average.
In part (a), majority of the candidates stated the condition under which the reaction occurs. They also listed the species that were oxidized and reduced.
In part (b), majority of the candidates were able to list five steps in the treatment of water for town supply. However, only few of them were able to describe the steps involved in the treatment of water.
In part (c), majority of the candidates were able to write the electron configuration of the elements listed.
In part (d), majority of the candidates could not calculate the number of moles of hydrogen ions in 1 dm3 of a 0.1 mol dm-3 tetraoxosulphate (VI) acid solution.
The expected answers include:
(a) (i) Acidic medium/heat    
    (ii)  I.C2O42-           
    II.  MnO4- 
    (iii) MnO4- + 8H+  + 5e- → Mn2+ + 4H2O  
                                                                                                              
    (b)  (i) Aeration
    Coagulation/Flocculation/Addition  of alum
    Sedimentation
    Filtration
    Chlorination/disinfection/killing  bacteria
    Supplementation/addition  of fluorine/iodine
    pH  measurement/regulation
                                                                                                  
  (ii) Aeration - exposure to air and sunlight
    
 Coagulation - addition of alum brings about the  coagulation of dirt particles  in the water    
    
Sedimentation  - the coagulated dirt particles sink to the bottom of the  vessel        
    
Filtration  - the use of sand bed (to bring about effective filtration  of the water from foreign particles)
    
Chlorination     - addition of chlorine to the water  (kills all inherent germs  in the water making the water
    chemically  safe for drinking)
    
Supplementation - addition of other  chemicals like fluorine and iodine supplements  the usefulness of the water being purified  to the human body    
    
pH measurement - addition of calculated  amount of CaO or quicklime 
                                        
    (c)        (i)         12Q -  1s2 2s2 2p6  3s2  
17R - 1s2 2s2 2p6 3s2 3p5
                        20S -  1s2 2s2 2p6  3s2 3p6 4s2  
    (ii)  Chemical properties depend on the number  of valence electrons. Q and S have  the same number of valence electrons/2 electrons in the valence shell hence  similar chemical properties.  Q and R have different valence electrons, hence different chemical  properties.
    
    (iii) SR2     
                                                                                                                          
    (d)       H2SO4(aq)  → 2H+(aq) + SO42-(aq)
    from  the equation; 1 mole of acid    2 moles of H+ ions   
    0.1 mole acid 0.1 x 2    
    1
    =     0.2 moles