Majority of the candidates were reported to have performed well in this ~uestion. They were able to expand and differentiate the given equation y = x (3-x ) with
respect to x to obtain dy= 3 - 3x2, substitute x = 2 into dy = 3 - 3x2 and
                                        dx                                                     dx
simplified to obtain the gradient of the normal as 1/9. Thus, the equation of the normal at the point x = 2 was obtained by finding the value of y when x = 2 from

the curve and applying appropriate rule such as y+2 = ~ to obtain x - 9y - 20 = O