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Physics Paper 2, MAy/June. 2009  
Questions: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 Main
General Comments
Weakness/Remedies
Strength























Question 2

A particle is projected horizontally at 15ms-1 from a height of 20m.
Calculate the horizontal distance covered by the particle just before hitting the ground.

[g = 10 ms-2]

Many candidates gave acceptable responses to register high performance.  However, few failed to apply the appropriate formula.


_____________________________________________________________________________________________________
Observation

The expected answer is:

Let R represent the horizontal distance covered at time, t.

                  h   = ½ gt2                                                                                                
                  20  = ½ x 10 x t2                                                                                      
                   
                        t  = 2 s                                                                                                

                        R  = ut                                                                                                            

                        =  15 x 2                                                                                                         
           
                          = 30m                                   
                                               

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