The Chief Examiner reported that this question was the most unpopular question and majority of those who attempted it performed poorly.
In part (a), candidates were expected respond as follows:
 x + y =  +  =. Therefore, |x + y| =  = 5 = 7.1.
In part (b), candidates were expected to show that if M(x, y) was the midpoint of  , then x =  = 2 and y =  = 1. Hence, the required point was M(2, 1). Similarly, if S(x, y) was the midpoint of , then, x =  = 5 and y =  = -1. Therefore, the midpoint of  was S(5, -1).  =  -  = . Similarly,  =  - = . By comparing the two vectors they would conclude that  = 2. To find the equation of, candidates would first find the gradient of  as  = . The required equation was y – 1 =(x – 2) which simplified to 2x + 3y = 7.