Home Technical Mathematics Languages Science Social Science Art Literature Arabic Islamic Studies C.R.K HistoryMusicVisual Art Clothing/Textile Home Management Shorthand
 General Mathematics Paper 2, Nov/Dec. 2009
 Questions: 1 2 3 4 5 6 7 8 9 10 11 12 13 Main
Weakness/Remedies
Strength
Question 8

The area of a rectangular football field is 7200m2 while its perimeter is 360m.  calculate the:

1. dimensions of the field;
2. cost of clearing the field at N6.50 per square meter, leaving a margin of 2m wide along the longer sides;
3. percentage of the part not cleared.
_____________________________________________________________________________________________________
Observation

It was reported that majority of the candidates who attempted this question were able to derive the two equations i.e. if x = length of field and y = breadth, then
xy = 7200; x + y = 180.  They were able to solve these equations and also obtained the dimensions as 60m and 120m.  However, attempt on the parts (b) and (c) was poorly handed by some of the candidates.  Many took the margin to be all round the field but the question specified along the longer sides.  Thus cost of clearing the field = N6.50 x 56 x 120 = N43,680.00.  The percentage of the part not cleared
= 7200 – (120 x 56) x 100  =  62/3 or 6.67%
7200
Candidates, who sketched the diagram, were reported to have performed well in the question.